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найдите минимум функции y=x^3+5x^2+7x+5
найдите минимум функции y=x^3+5x^2+7x+5-Divide both sides of the equation by 5 to have 1 as the coefficient of the first term x2 (7/5)x (3/5) = 0 Add 3/5 to both side of the equation x2 (7/5)x = 3/5 Now the clever bit Take the coefficient of x , which is 7/5 , divide by two, giving 7/10 , and finally square it giving 49/100Tangents to the curve y=x^33x^27x6 cut off on the negative semi axis OX a line segment half that on the positive semi axis OY is Tangents to the curve y = x 3 − 3 x 2 − 7 x 6 cut off on the negative semi axis O X a line segment half that on the positive semi axis O Y is
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78mathematics 37 Y 4 8 X 2 37 Answer Dy 2x4 8 X 2 Ln4dx 38 Y Ln 6x 3 5x 2 3 Answer Dy 38 3 18x 2 10x Dx 6x 3 5x 2 39 Y 4x 5 7x 3 4 4 39 Answer Course Hero
Free functions inverse calculator find functions inverse stepbystepCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history21 Factoring 7x 25x2 The first term is, 7x 2 its coefficient is 7 The middle term is, 5x its coefficient is 5 The last term, "the constant", is 2 Step1 Multiply the coefficient of the first term by the constant 7 • 2 = 14 Step2 Find two factors of 14 whose sum equals the coefficient of the middle term, which is 5
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Simple and best practice solution for y=(x2)(x3)(x7) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homeworkFree equations calculator solve linear, quadratic, polynomial, radical, exponential and logarithmic equations with all the steps Type in any equation to get the solution, steps and graphRemainder of x^32x^25x7 divided by x3;
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Quotient of x^38x^217x6 with x3;Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorMay 16, 17 · # y=x^35x^2 # Then differentiating wrt #x#, gives us # dy/dx = 3x^210x# Now comparing the the line equation #y=11xpi# to that of a line in standard form, #y=mxc#, we see immediately that #m=11# So any tangent to our curve that is parallel must have this same gradient This will occur if and only if
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